C语言实现万年历（c语言做万年历）

本文实例为大家分享了C语言实现简单万年历的具体代码，供大家参考，具体内容如下

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 #include <stdio.h> #include<stdlib.h> int year, month; int run[12] = { 31,29,31,30,31,30,31,31,30,31,30,31 }; int ping[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 }; char week[7][10] = { "SUN","MON","TUE","WED","THU","FRI","SAT" }; bool IsLeap(int year) { if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) //判断闰年 { return true; } else { return false; } } void PrintStar() { printf("\t\t\t万年历\t\t\t\n"); printf("****************************************************\n"); for (int i = 0; i < 7; i++) { printf("%s\t", week[i]); } printf("\n"); } int DaySum(int year, int month) { int sum = 0; for (int i = 1990; i < year; i++) { if (IsLeap(i)) { sum += 366; } else { sum += 365; } } for (int i = 0; i < month - 1; i++) { if (IsLeap(year)) { sum += run[i]; } else { sum += ping[i]; } } return sum; } void PrintCal(int sum, int year, int month) { int nRes, nTmp; nRes = sum % 7+1;//前面空几格 nTmp = 7 - nRes;//从第几格开始打印 for (int i = 0; i < nRes; i++) { printf("\t"); } if (IsLeap(year)) { for (int i = 1; i < run[month - 1]+1; i++) { printf("%d\t", i); if (nTmp == i || (i - nTmp) % 7 == 0) { printf("\n"); } } printf("\n"); } else { for (int i = 1; i < ping[month - 1]+1; i++) { printf("%d\t", i); if (nTmp == i || (i - nTmp) % 7 == 0) { printf("\n"); } } printf("\n"); } } int main(void) { while (1) { scanf_s("%d %d", &year, &month); PrintStar(); PrintCal(DaySum(year, month), year, month); printf("****************************************************\n"); } return 0; }